DONATSciences and Maths
Biology · Simulation and virtual lab Free

Food tests: starch, sugars, protein, fats and vitamin C

Test real Rwandan foods with iodine, Benedict’s, Biuret, ethanol and DCPIP, and find out what an unknown food contains.

  • Best for S2 · Unit 4: Identification of food components
  • Also useful S1 · Unit 7: Food nutrients and diet (which foods contain which nutrients)
  • Also useful S3 · Unit 6: Heterotrophic nutrition (nutrients digested in the gut)
You will learn to
  • Carry out food tests for starch, reducing and non-reducing sugars, protein and lipids.
  • Use a control and record observations correctly.
  • Compare the vitamin C content of juices with DCPIP.
You will measure
Colour changes; volume of juice (cm³) to decolourise DCPIP; vitamin C in mg per 100 cm³.
Time needed
About 35–45 min
Equipment
Nothing extra. Real version: test tubes, iodine, Benedict’s, Biuret reagents, ethanol, DCPIP, water bath, food samples.
Price
Free: no payment, no account.

Simulation

Ugali, beans, milk, groundnuts and fruit juice give us different nutrients. Food scientists and nutritionists use simple chemical tests to find what a food contains.

Change and observe

Virtual lab

Follow the steps with the simulation above (go back to the simulation ↑). Each time you tap Record, a row is added to the table and a point to the graph.

Aim

To identify starch, reducing and non-reducing sugars, proteins, lipids and vitamin C in food samples, and to compare the vitamin C content of fruit juices.

What to do

  1. Choose Maize flour and the iodine test. Add iodine, observe and record. Repeat with distilled water as a control.
  2. Choose Glucose and the Benedict’s test. Add Benedict’s solution, heat for 5 minutes and record the colour.
  3. Test table sugar with Benedict’s. Then use the non-reducing sugar test: boil with acid, neutralise, add Benedict’s and heat.
  4. Test egg white with the Biuret test and cooking oil with the ethanol emulsion test.
  5. Use the DCPIP test on the vitamin C standard, then on orange, lemon and tomato juice. Record the volume needed each time.
  6. Do all the tests on Unknown food X and write what it contains.

Results

📏 Read the instruments carefully

InstrumentSmallest readingUncertainty
Dropper / pipette1 drop (≈ 0.05 cm³)± 1 drop
Syringe (DCPIP test)0.1 cm³± 0.05 cm³
Water bath thermometer1 °C± 0.5 °C; keep it near boiling
Colour judgement—compare with a control tube and a white background

Write every reading with its unit, and with the same number of decimal places as the instrument. Use the 🔍 Magnifier on the picture to read small scales at eye level.

⚠️ Avoid these mistakes

  • Not heating the Benedict’s test: the colour stays blue even if sugar is present.
  • Forgetting to neutralise after boiling with acid in the non-reducing sugar test.
  • Heating ethanol over a flame: it is flammable. Use a water bath and keep flames away.

✍️ Conclusion

Write your own conclusion first: what do your results and graph show, and which law or principle do they support?

Check your conclusion

Each nutrient gives its own colour change: starch turns iodine blue-black, reducing sugars turn hot Benedict’s solution green to brick red, protein turns Biuret purple, lipids give a milky emulsion, and vitamin C decolourises DCPIP. The smaller the volume of juice needed to decolourise DCPIP, the more vitamin C it contains.

Questions

What is the colour of a positive starch test?

Iodine changes from orange-brown to blue-black.

Why must Benedict’s test be heated?

The reducing sugar only reduces the copper(II) ions in Benedict’s solution when heated in a boiling water bath; without heating the colour stays blue.

Why does sucrose give a negative Benedict’s test at first?

Sucrose is a non-reducing sugar. It must first be hydrolysed (broken down) into glucose and fructose by boiling with acid.

Why must the acid be neutralised before adding Benedict’s solution?

Benedict’s test only works in alkaline conditions.

Why is distilled water tested as well?

It is a control: it shows the colour of a negative result, so we can compare.

Juice A decolourises DCPIP with 0.5 cm³ and juice B with 1.5 cm³. Which has more vitamin C?

Juice A, because a smaller volume contains enough vitamin C to decolourise the same amount of DCPIP.

For teachers: expected results and how the model works

Benedict’s colours: blue (none), green (trace), yellow-orange (moderate), brick red (much reducing sugar). Heating takes 10 s of real time for 5 simulated minutes. Sucrose is negative until acid hydrolysis AND neutralisation. DCPIP: 1 cm³ is decolourised by 0.25 mg of vitamin C (standard 0.10 mg/cm³ needs 2.5 cm³; orange 0.5 cm³ ≈ 50 mg/100 cm³; lemon ≈ 45; tomato ≈ 15). Unknown X is random each time it is chosen.

Quick check 3 questions · scored

Choose one answer for each question. You see at once if it is right, why, and your score at the end.

1. Which reagent tests for starch?

2. After heating with Benedict’s solution a sample turns brick red. What does it contain?

3. Juice A decolourises DCPIP with 0.4 cm³, juice B with 1.2 cm³. Which has more vitamin C?

Exam practice Exam set

National-exam style questions on this simulation (13 marks). Try each one on paper first, then open the marking scheme.

Describe how you would test a sample of milk for protein, giving the reagents and the positive result. (3 marks)

Marking scheme: Add sodium hydroxide solution to the milk (1), then a few drops of dilute copper(II) sulfate (Biuret test) (1); a purple/violet colour shows protein (1).

A student tests a food: iodine stays orange-brown; Benedict’s gives brick red; Biuret stays blue; the emulsion test gives a milky layer. State what the food contains and what it does not contain. (4 marks)

Marking scheme: Contains reducing sugar (1) and lipid (1). No starch (1) and no protein (1).

1 cm³ of DCPIP is decolourised by 2.5 cm³ of a vitamin C solution of 0.10 mg/cm³ and by 0.50 cm³ of orange juice. Calculate the vitamin C content of the juice in mg per 100 cm³. (4 marks)

Marking scheme: Vitamin C needed = 2.5 × 0.10 = 0.25 mg (1). Juice: 0.25 mg in 0.50 cm³ (1) = 0.50 mg/cm³ (1) = 50 mg per 100 cm³ (1).

Give two safety precautions when carrying out food tests. (2 marks)

Marking scheme: Wear eye protection / point test tubes away from people when heating (1); use a water bath, not a direct flame, for ethanol; handle sodium hydroxide and acid with care (1).

For class and homework

Teacher resources

The worksheet has the steps, an empty results table, a graph grid and all the questions with answer lines. The marking scheme has the expected results and every answer with its marks.

Keep learning

This simulation is an original model made for Rwandan learners. Real experiments can give slightly different numbers: a simulation never replaces handling real apparatus when your school has it.